What is the compound interest on Rupees 8000 at 10% pa for 2 years if the interest is calculated half yearly?

Answer

What is the compound interest on Rupees 8000 at 10% pa for 2 years if the interest is calculated half yearly?
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Hint: making use of the formula of compound interest.
$p {\left( {1 + \dfrac{R}{{100}}} \right)^t}$. Where P is Principal, R is Rate, t is time.Complete step-by-step answer:

In the given question we are provided
Principle, P=8000
Rate, R=5%
Time, t=3
Making use of formula
$P {\left( {1 + \dfrac{R}{{100}}} \right)^t}$. Substitute the values in this formula, we get
$
  8000{\left( {1 + \dfrac{5}{{100}}} \right)^3} \\
   = 8000{\left( {\dfrac{{105}}{{100}}} \right)^3} \\
   = 8000 \times \dfrac{{105}}{{100}} \times \dfrac{{105}}{{100}} \times \dfrac{{105}}{{100}} \\
   = 9261 \\
 $
So compound interest is 9261.

Note: For per annum compound interest is calculated for the whole year. But if in a question it was asked for half-yearly too we have to take a time period of 6 months. The calculation should be done properly.

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IB ACIO Grade-II: Full Mock Test

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Given:

P = 8000

R = 20% p.a.

T = 18 months

Formula used:

A = P [1 + (R/100)]n

Where, n → Number of years, P → Principal Amount, R → Rate of Interest, A → Amount

Calculation:

Here interest is compounded half-yearly.

R = 20/2% = 10%

⇒ n = 18/6 = 3

⇒ R = 10% , n = 3

A = P [1 + (R/100)]n

⇒ A = 8000 × [1 + (10/100)]3

⇒ A = 8000 × (11/10)3

⇒ A = 8000 × 11 × 11 × 11/1000

⇒ A = 8 × 1331

⇒ A = 10,648

Amount earned is Rs 10,648

Last updated on Sep 21, 2022

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Let's discuss the concepts related to Interest and Compound Interest. Explore more from Quantitative Aptitude here. Learn now!

What is compound interest on 8000 at 10% pa for 2 year if the interest is calculated half yearly?

<br>So , Compound Interest `=` Rs `9261 -` Rs `8000 =` Rs `1261`.

What is the compounded annual interest for a loan amount of Rs 8000 at 10% per annum for a period of 2 years?

8000Period (n) = 2 yearsRate (R1)=9% for the first yearR2=10% the second year∴ Amount (A)= P (1+R1100)1(1+R2100)1=8000 (1+9100) (1+10100)=Rs. 8000×109100×110100=Rs. 9592. Q.

What is the compound interest on $1000 at 10% per annum for 2 years compounded annually?

compound interest after 2yrs of 1000 Rs at the rate 10% per annum is 210 Rs. it is given that principal , P = 1000 Rs. = 210 Rs. ∴Hence, compound interest = 210 Rs.

In what time will rupees 8000 earn rupees 1261 as CI at 10% pa compounded half yearly?

8000Rate (R)= 10% p. a. or 5% half yearlyPeriod (n) = 1 year or 2 half years∴ Amount after 1 year (A)= P(1+R100)n=Rs. 8000×(1+5100)2=Rs. 8000×(2120)2=Rs.