What is the relationship between the wavelength of light and the quantity of energy per photon?

What is the relationship between the wavelength of light and the quantity of energy per photon?
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We can think of radiation either as waves or as individual particles called photons. The energy associated with a single photon is given by E = hν , where E is the energy (SI units of J), h is Planck's constant (h = 6.626 x 10–34 J s), and ν is the frequency of the radiation (SI units of s–1 or Hertz, Hz) (see figure below). Frequency is related to wavelength by λ=c/ν , where c, the speed of light, is 2.998 x 108 m s–1. Another quantity that you will often see is wavenumber, σ=1/λ, which is commonly reported in units of cm–1.

The energy of a single photon that has the wavelength λ is given by:

E = hcλ= 1.986× 10−16 J nm photon−1 λMathType@MTEF@5@5@+=faaagCart1ev2aaaKnaaaaWenf2ys9wBH5garuavP1wzZbItLDhis9wBH5garmWu51MyVXgaruWqVvNCPvMCaerbdfwBIjxAHbqee0evGueE0jxyaibaieYlf9irVeeu0dXdh9vqqj=hHeeu0xXdbba9frFj0=OqFfea0dXdd9vqaq=JfrVkFHe9pgea0dXdar=Jb9hs0dXdbPYxe9vr0=vr0=vqpi0dc9GqpWqaaeaabiGaciaacaqabeaadaabauaaaOqaaabbaaaaaaaaIXwyJTgapeGaamyraiaabckacqGH9aqpcaqGGcWaaSaaaeaacaWGObGaam4yaaqaaiabeU7aSbaacqGH9aqpcaqGGcWaaSaaa8aabaWdbiaaigdacaGGUaGaaGyoaiaaiIdacaaI2aGaey41aqRaaeiOaiaaigdacaaIWaWdamaaCaaaleqabaWdbiabgkHiTiaaigdacaaI2aaaaOGaaeiOaiaabQeacaqGGaGaaeOBaiaab2gacaqGGcGaaeiCaiaabIgacaqGVbGaaeiDaiaab+gacaqGUbWdamaaCaaaleqabaWdbiabgkHiTiaaigdaaaaak8aabaWdbiabeU7aSbaaaaa@5AA2@

[6.2a]

Note that as the wavelength of light gets shorter, the energy of the photon gets greater. The energy of a mole of photons that have the wavelength λ is found by multiplying the above equation by Avogadro's number:

Em = hcNAλ=  1.196 × 108 J nm mol−1λMathType@MTEF@5@5@+=faaagCart1ev2aaaKnaaaaWenf2ys9wBH5garuavP1wzZbItLDhis9wBH5garmWu51MyVXgaruWqVvNCPvMCaerbdfwBIjxAHbqee0evGueE0jxyaibaieYlf9irVeeu0dXdh9vqqj=hHeeu0xXdbba9frFj0=OqFfea0dXdd9vqaq=JfrVkFHe9pgea0dXdar=Jb9hs0dXdbPYxe9vr0=vr0=vqpi0dc9GqpWqaaeaabiGaciaacaqabeaadaabauaaaOqaaabbaaaaaaaaIXwyJTgapeGaamyra8aadaWgaaWcbaWdbiaad2gaa8aabeaak8qacaqGGcGaeyypa0JaaeiOamaalaaabaGaamiAaiaadogacaWGobWdamaaBaaaleaapeGaamyqaaWdaeqaaaGcpeqaaiabeU7aSbaacqGH9aqpcaqGGcWaaSaaa8aabaWdbiaaigdacaGGUaGaaGymaiaaiMdacaaI2aGaaeiOaiabgEna0kaabckacaaIXaGaaGima8aadaahaaWcbeqaa8qacaaI4aaaaOGaaeiiaiaabQeacaqGGaGaaeOBaiaab2gacaqGGcGaaeyBaiaab+gacaqGSbWdamaaCaaaleqabaWdbiabgkHiTiaaigdaaaaak8aabaWdbiabeU7aSbaaaaa@5A32@

[6.2b]

 

What is the relationship between the wavelength of light and the quantity of energy per photon?

Energy scales: penetration through Earth’s atmosphere; radiation name by wavelength; physical object the size of that wavelength; frequency compared to wavelength; and temperature of an object that has its peak radiation at each wavelength.

In the lesson on atmospheric composition, you saw how solar UV radiation was able to break apart molecules to initiate atmospheric chemistry. These molecules are absorbing the energy of a photon of radiation, and if that photon energy is greater than the strength of the chemical bond, the molecule may break apart.

Check Your Understanding

Consider the reaction O3 + UV → O2 + O*. If the bond strength between O2 and O* (i.e., excited state oxygen atom) is 386 kJ mol–1, what is the longest wavelength that a photon can have and still break this bond?

Click for answer.

ANSWER: Solve for wavelength in equation [6.2b]

λ= 1.196 ×  108 J nm mol−1Em =1.196 × 108 J nm mol−1386  × 103 J mol−1=309 nmMathType@MTEF@5@5@+=faaagCart1ev2aaaKnaaaaWenf2ys9wBH5garuavP1wzZbItLDhis9wBH5garmWu51MyVXgaruWqVvNCPvMCaerbdfwBIjxAHbqee0evGueE0jxyaibaieYlf9irVeeu0dXdh9vqqj=hHeeu0xXdbba9frFj0=OqFfea0dXdd9vqaq=JfrVkFHe9pgea0dXdar=Jb9hs0dXdbPYxe9vr0=vr0=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@817C@

What is the relationship between wavelength of light and the quantity of energy per photon?

The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.
The energy E of a photon is equal to hv = hc/λ, where v is the frequency of the electromagnetic radiation and λ is its wavelength.

What is the relationship between the energy of light and its frequency?

Just as wavelength and frequency are related to light, they are also related to energy. The shorter the wavelengths and higher the frequency corresponds with greater energy. So the longer the wavelengths and lower the frequency results in lower energy. The energy equation is E = hν.

What is the wavelength of the radiation with photon energy?

1 Answer. ⇒λ3=4800Å ⇒ λ 3 = 4800 Å .